Integrand size = 17, antiderivative size = 84 \[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=-\frac {a^3 \left (a+b x^n\right )^6}{6 b^4 n}+\frac {3 a^2 \left (a+b x^n\right )^7}{7 b^4 n}-\frac {3 a \left (a+b x^n\right )^8}{8 b^4 n}+\frac {\left (a+b x^n\right )^9}{9 b^4 n} \]
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Time = 0.03 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {272, 45} \[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=-\frac {a^3 \left (a+b x^n\right )^6}{6 b^4 n}+\frac {3 a^2 \left (a+b x^n\right )^7}{7 b^4 n}+\frac {\left (a+b x^n\right )^9}{9 b^4 n}-\frac {3 a \left (a+b x^n\right )^8}{8 b^4 n} \]
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Rule 45
Rule 272
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int x^3 (a+b x)^5 \, dx,x,x^n\right )}{n} \\ & = \frac {\text {Subst}\left (\int \left (-\frac {a^3 (a+b x)^5}{b^3}+\frac {3 a^2 (a+b x)^6}{b^3}-\frac {3 a (a+b x)^7}{b^3}+\frac {(a+b x)^8}{b^3}\right ) \, dx,x,x^n\right )}{n} \\ & = -\frac {a^3 \left (a+b x^n\right )^6}{6 b^4 n}+\frac {3 a^2 \left (a+b x^n\right )^7}{7 b^4 n}-\frac {3 a \left (a+b x^n\right )^8}{8 b^4 n}+\frac {\left (a+b x^n\right )^9}{9 b^4 n} \\ \end{align*}
Time = 0.05 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.88 \[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=\frac {x^{4 n} \left (126 a^5+504 a^4 b x^n+840 a^3 b^2 x^{2 n}+720 a^2 b^3 x^{3 n}+315 a b^4 x^{4 n}+56 b^5 x^{5 n}\right )}{504 n} \]
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Time = 4.34 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.04
method | result | size |
risch | \(\frac {b^{5} x^{9 n}}{9 n}+\frac {5 a \,b^{4} x^{8 n}}{8 n}+\frac {10 a^{2} b^{3} x^{7 n}}{7 n}+\frac {5 a^{3} b^{2} x^{6 n}}{3 n}+\frac {a^{4} b \,x^{5 n}}{n}+\frac {a^{5} x^{4 n}}{4 n}\) | \(87\) |
parallelrisch | \(\frac {56 x \,x^{5 n} x^{-1+4 n} b^{5}+315 x \,x^{4 n} x^{-1+4 n} a \,b^{4}+720 x \,x^{3 n} x^{-1+4 n} a^{2} b^{3}+840 x \,x^{2 n} x^{-1+4 n} a^{3} b^{2}+504 x \,x^{n} x^{-1+4 n} a^{4} b +126 x \,x^{-1+4 n} a^{5}}{504 n}\) | \(116\) |
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Time = 0.26 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.88 \[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=\frac {56 \, b^{5} x^{9 \, n} + 315 \, a b^{4} x^{8 \, n} + 720 \, a^{2} b^{3} x^{7 \, n} + 840 \, a^{3} b^{2} x^{6 \, n} + 504 \, a^{4} b x^{5 \, n} + 126 \, a^{5} x^{4 \, n}}{504 \, n} \]
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Time = 0.75 (sec) , antiderivative size = 136, normalized size of antiderivative = 1.62 \[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=\begin {cases} \frac {a^{5} x x^{4 n - 1}}{4 n} + \frac {a^{4} b x x^{n} x^{4 n - 1}}{n} + \frac {5 a^{3} b^{2} x x^{2 n} x^{4 n - 1}}{3 n} + \frac {10 a^{2} b^{3} x x^{3 n} x^{4 n - 1}}{7 n} + \frac {5 a b^{4} x x^{4 n} x^{4 n - 1}}{8 n} + \frac {b^{5} x x^{5 n} x^{4 n - 1}}{9 n} & \text {for}\: n \neq 0 \\\left (a + b\right )^{5} \log {\left (x \right )} & \text {otherwise} \end {cases} \]
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Time = 0.19 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.02 \[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=\frac {b^{5} x^{9 \, n}}{9 \, n} + \frac {5 \, a b^{4} x^{8 \, n}}{8 \, n} + \frac {10 \, a^{2} b^{3} x^{7 \, n}}{7 \, n} + \frac {5 \, a^{3} b^{2} x^{6 \, n}}{3 \, n} + \frac {a^{4} b x^{5 \, n}}{n} + \frac {a^{5} x^{4 \, n}}{4 \, n} \]
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\[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=\int { {\left (b x^{n} + a\right )}^{5} x^{4 \, n - 1} \,d x } \]
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Time = 5.83 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.02 \[ \int x^{-1+4 n} \left (a+b x^n\right )^5 \, dx=\frac {a^5\,x^{4\,n}}{4\,n}+\frac {b^5\,x^{9\,n}}{9\,n}+\frac {5\,a^3\,b^2\,x^{6\,n}}{3\,n}+\frac {10\,a^2\,b^3\,x^{7\,n}}{7\,n}+\frac {a^4\,b\,x^{5\,n}}{n}+\frac {5\,a\,b^4\,x^{8\,n}}{8\,n} \]
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